Find concentration for 0.15 mol in 0.50 L of solution.
Answer and explanation
0.3 mol/L
c = 0.15/0.50 = 0.30.
Subjects
Choose questions individually, practise online, or create a worksheet with matching answers. Counts include generated variants, not only authored originals.
0.3 mol/L
c = 0.15/0.50 = 0.30.
0.25 L
Divide milliliters by 1000.
0.1 mol/L
c₂ = 0.50 × 20/100 = 0.10.
The amount of solute.
Adding solvent lowers concentration but preserves solute amount.
0.08 mol
n = cV = 0.40 × 0.20 = 0.080.
The concentration depends on the total final solution volume.
Assuming volume addition can also be inaccurate for some mixtures.
Count solute amount before and after adding solvent.
Grades 9–12Count solute amount before and after adding solvent.
Grades 9–12Use the balanced mole ratio and distinguish endpoint from equivalence.
Grades 10–12Use the balanced mole ratio and distinguish endpoint from equivalence.
Grades 10–12Interpret a supplied chromatogram without claiming one spot proves identity.
Grades 9–12Interpret a supplied chromatogram without claiming one spot proves identity.
Grades 9–12Use the supplied relationship within its validated range.
Grades 10–12Use the supplied relationship within its validated range.
Grades 10–12Do not confuse an impure recovered mass with a chemical yield.
Grades 10–12Do not confuse an impure recovered mass with a chemical yield.
Grades 10–12For concentration in mol/L, convert the final solution volume from mL to L before multiplying.
Grades 9–12Divide moles of solute by the final solution volume in litres, not by solvent volume alone.
Grades 9–12Final volume is the total solution volume; assume no reaction or solute loss.
Grades 9–12Use total solution mass in the denominator: solute plus solvent. Multiply the fraction by 100.
Grades 8–11Convert purity percent to a fraction before multiplying the total sample mass.
Grades 9–12Compare actual pure product with the theoretical maximum in the same units. Yield and purity are different quantities.
Grades 9–12Use the balanced equation, not an assumed one-to-one ratio. Here each formula unit supplies two hydroxide ions.
Grades 10–12Measure both distances from the same origin. Rf is dimensionless and depends on the chromatographic conditions.
Grades 9–12Subtract the intercept or blank first, then divide by the slope. Use the model only within its stated calibration range.
Grades 10–12Formula reference
Grades 8–12Formula reference
Grades 9–12