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Chemistry · Grades 9–12

Amount and concentration

Divide moles of solute by the final solution volume in litres, not by solvent volume alone.

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Rule and assumptions

Divide moles of solute by the final solution volume in litres, not by solvent volume alone.

c = n/V

Worked examples

A model solution contains 3.7 mol in a final volume of 1.15 L. Find its molar concentration. Round to 3 decimal places if needed. Answer in mol/L.

c = n/V 3.7/1.15 = 3.217

3.217 mol/L

A model solution contains 4 mol in a final volume of 1.77 L. Find its molar concentration. Round to 3 decimal places if needed. Answer in mol/L.

c = n/V 4/1.77 = 2.26

2.26 mol/L

Try two questions

  1. A model solution contains 2.6 mol in a final volume of 0.67 L. Find its molar concentration. Round to 3 decimal places if needed. Answer in mol/L.

  2. A model solution contains 2 mol in a final volume of 1.15 L. Find its molar concentration. Round to 3 decimal places if needed. Answer in mol/L.

Answers and reasoning

Answers and marking notes
  1. 3.881 mol/L

    c = n/V 2.6/0.67 = 3.881

  2. 1.739 mol/L

    c = n/V 2/1.15 = 1.739

Further reading and review references

These are reference links, not copied exercises, institutional endorsement or proof of independent review.

Learning preview · independent educational and translation review required. Suggested grades are not official curriculum alignment.