Grade 12 · Maths · curriculum collection
Grade 12 Maths, Common Core conceptual categories
8 units for Grade 12 maths, organised by Common Core conceptual category: Algebra, Functions, Geometry, Statistics and Probability. Each unit has a short lesson, a practice worksheet and a review worksheet, both with answer keys.
Answer-checked and approved on 29 October 2026
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Aligned by StudyBrix at domain level. Not an official publication of, or endorsed by, the standards' authors. Framework: Common Core State Standards for Mathematics.
Units in teaching order
HS.A Algebra
Quadratic expressions and equations
The discriminant and completing the square.
Short lesson: Complete the square
Study guide for Grades 9 to 12: 2 worked examples and 2 practice questions. Halve the coefficient of x, then square it.
x² + 2hx + h² = (x + h)²
Halve the coefficient of x, then square it.
Worked example
Complete x² + 68x + □ = (x + 34)².
(68 ÷ 2)² = 1156
Answer: 1156
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
Find the discriminant of 8x² + 11x + 15 = 0.
Complete x² + 38x + □ = (x + 19)².
Find the discriminant of 2x² + 8x + 17 = 0.
Complete x² + 60x + □ = (x + 30)².
Find the discriminant of 2x² + 15x + 1 = 0.
Complete x² + 62x + □ = (x + 31)².
Find the discriminant of 2x² + 16x + 5 = 0.
Complete x² + 8x + □ = (x + 4)².
Find the discriminant of 8x² + 18x + 18 = 0.
Complete x² + 56x + □ = (x + 28)².
Find the discriminant of 8x² + 4x + 5 = 0.
Complete x² + 80x + □ = (x + 40)².
Answer key
- -359 11² − 4 × 8 × 15 = -359
- 361 (38 ÷ 2)² = 361
- -72 8² − 4 × 2 × 17 = -72
- 900 (60 ÷ 2)² = 900
- 217 15² − 4 × 2 × 1 = 217
- 961 (62 ÷ 2)² = 961
- 216 16² − 4 × 2 × 5 = 216
- 16 (8 ÷ 2)² = 16
- -252 18² − 4 × 8 × 18 = -252
- 784 (56 ÷ 2)² = 784
- -144 4² − 4 × 8 × 5 = -144
- 1600 (80 ÷ 2)² = 1600
Review worksheet: 12 questions
Find the discriminant of 8x² + 18x + 2 = 0.
Complete x² + 68x + □ = (x + 34)².
Find the discriminant of 1x² + 16x + 8 = 0.
Complete x² + 48x + □ = (x + 24)².
Find the discriminant of 6x² + 16x + 17 = 0.
Complete x² + 26x + □ = (x + 13)².
Find the discriminant of 7x² + 1x + 19 = 0.
Complete x² + 66x + □ = (x + 33)².
Find the discriminant of 4x² + 1x + 7 = 0.
Complete x² + 30x + □ = (x + 15)².
Find the discriminant of 3x² + 20x + 2 = 0.
Complete x² + 36x + □ = (x + 18)².
Answer key
- 260 18² − 4 × 8 × 2 = 260
- 1156 (68 ÷ 2)² = 1156
- 224 16² − 4 × 1 × 8 = 224
- 576 (48 ÷ 2)² = 576
- -152 16² − 4 × 6 × 17 = -152
- 169 (26 ÷ 2)² = 169
- -531 1² − 4 × 7 × 19 = -531
- 1089 (66 ÷ 2)² = 1089
- -111 1² − 4 × 4 × 7 = -111
- 225 (30 ÷ 2)² = 225
- 376 20² − 4 × 3 × 2 = 376
- 324 (36 ÷ 2)² = 324
HS.A Algebra
Geometric series
Sums of geometric series.
Short lesson: Finite geometric sums
Study guide for Grades 10 to 12: 2 worked examples and 2 practice questions. Use n terms, starting with the first term a.
Sₙ = a(rⁿ − 1)/(r − 1), r ≠ 1
Use n terms, starting with the first term a.
Worked example
Find the sum of the first 4 terms of a geometric sequence with first term 4 and ratio 4.
4 × (4^4 − 1) ÷ (4 − 1) = 340
Answer: 340
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
Find the sum of the first 5 terms of a geometric sequence with first term 5 and ratio 4.
Find the sum of the first 3 terms of a geometric sequence with first term 15 and ratio 3.
Find the sum of the first 6 terms of a geometric sequence with first term 2 and ratio 4.
Find the sum of the first 6 terms of a geometric sequence with first term 15 and ratio 5.
Find the sum of the first 3 terms of a geometric sequence with first term 2 and ratio 4.
Find the sum of the first 4 terms of a geometric sequence with first term 7 and ratio 4.
Find the sum of the first 6 terms of a geometric sequence with first term 4 and ratio 4.
Find the sum of the first 7 terms of a geometric sequence with first term 6 and ratio 2.
Find the sum of the first 7 terms of a geometric sequence with first term 10 and ratio 2.
Find the sum of the first 7 terms of a geometric sequence with first term 7 and ratio 5.
Find the sum of the first 3 terms of a geometric sequence with first term 10 and ratio 5.
Find the sum of the first 6 terms of a geometric sequence with first term 6 and ratio 5.
Answer key
- 1705 5 × (4^5 − 1) ÷ (4 − 1) = 1705
- 195 15 × (3^3 − 1) ÷ (3 − 1) = 195
- 2730 2 × (4^6 − 1) ÷ (4 − 1) = 2730
- 58590 15 × (5^6 − 1) ÷ (5 − 1) = 58590
- 42 2 × (4^3 − 1) ÷ (4 − 1) = 42
- 595 7 × (4^4 − 1) ÷ (4 − 1) = 595
- 5460 4 × (4^6 − 1) ÷ (4 − 1) = 5460
- 762 6 × (2^7 − 1) ÷ (2 − 1) = 762
- 1270 10 × (2^7 − 1) ÷ (2 − 1) = 1270
- 136717 7 × (5^7 − 1) ÷ (5 − 1) = 136717
- 310 10 × (5^3 − 1) ÷ (5 − 1) = 310
- 23436 6 × (5^6 − 1) ÷ (5 − 1) = 23436
Review worksheet: 12 questions
Find the sum of the first 5 terms of a geometric sequence with first term 5 and ratio 2.
Find the sum of the first 4 terms of a geometric sequence with first term 6 and ratio 3.
Find the sum of the first 6 terms of a geometric sequence with first term 1 and ratio 2.
Find the sum of the first 3 terms of a geometric sequence with first term 9 and ratio 3.
Find the sum of the first 3 terms of a geometric sequence with first term 12 and ratio 5.
Find the sum of the first 6 terms of a geometric sequence with first term 13 and ratio 5.
Find the sum of the first 4 terms of a geometric sequence with first term 6 and ratio 4.
Find the sum of the first 5 terms of a geometric sequence with first term 11 and ratio 5.
Find the sum of the first 6 terms of a geometric sequence with first term 12 and ratio 3.
Find the sum of the first 7 terms of a geometric sequence with first term 11 and ratio 5.
Find the sum of the first 6 terms of a geometric sequence with first term 6 and ratio 2.
Find the sum of the first 5 terms of a geometric sequence with first term 7 and ratio 4.
Answer key
- 155 5 × (2^5 − 1) ÷ (2 − 1) = 155
- 240 6 × (3^4 − 1) ÷ (3 − 1) = 240
- 63 1 × (2^6 − 1) ÷ (2 − 1) = 63
- 117 9 × (3^3 − 1) ÷ (3 − 1) = 117
- 372 12 × (5^3 − 1) ÷ (5 − 1) = 372
- 50778 13 × (5^6 − 1) ÷ (5 − 1) = 50778
- 510 6 × (4^4 − 1) ÷ (4 − 1) = 510
- 8591 11 × (5^5 − 1) ÷ (5 − 1) = 8591
- 4368 12 × (3^6 − 1) ÷ (3 − 1) = 4368
- 214841 11 × (5^7 − 1) ÷ (5 − 1) = 214841
- 378 6 × (2^6 − 1) ÷ (2 − 1) = 378
- 2387 7 × (4^5 − 1) ÷ (4 − 1) = 2387
HS.F Functions
Inverse and composite functions
Composing functions.
Short lesson: Compose two functions
Study guide for Grades 9 to 12: 2 worked examples and 2 practice questions. Apply the inside function first.
(f ∘ g)(x) = f(g(x))
Apply the inside function first.
Worked example
f(t) = 4t + (-3); g(t) = 5t + (-5). Find f(g(7)).
g(7) = 30; f(30) = 117
Answer: 117
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
f(t) = 2t + (1); g(t) = 6t + (0). Find f(g(-3)).
f(t) = 3t + (-7); g(t) = 2t + (6). Find f(g(-3)).
f(t) = 3t + (-10); g(t) = 3t + (-4). Find f(g(3)).
f(t) = 6t + (-3); g(t) = 8t + (6). Find f(g(2)).
f(t) = 7t + (-9); g(t) = 8t + (-4). Find f(g(-3)).
f(t) = 3t + (1); g(t) = 2t + (-8). Find f(g(0)).
f(t) = 9t + (5); g(t) = 8t + (-6). Find f(g(4)).
f(t) = 8t + (-8); g(t) = 2t + (-4). Find f(g(-3)).
f(t) = 3t + (-10); g(t) = 2t + (6). Find f(g(3)).
f(t) = 7t + (-1); g(t) = 6t + (-2). Find f(g(-3)).
f(t) = 5t + (3); g(t) = 1t + (-6). Find f(g(-1)).
f(t) = 7t + (-4); g(t) = 6t + (6). Find f(g(-2)).
Answer key
- -35 g(-3) = -18; f(-18) = -35
- -7 g(-3) = 0; f(0) = -7
- 5 g(3) = 5; f(5) = 5
- 129 g(2) = 22; f(22) = 129
- -205 g(-3) = -28; f(-28) = -205
- -23 g(0) = -8; f(-8) = -23
- 239 g(4) = 26; f(26) = 239
- -88 g(-3) = -10; f(-10) = -88
- 26 g(3) = 12; f(12) = 26
- -141 g(-3) = -20; f(-20) = -141
- -32 g(-1) = -7; f(-7) = -32
- -46 g(-2) = -6; f(-6) = -46
Review worksheet: 12 questions
f(t) = 7t + (10); g(t) = 3t + (8). Find f(g(8)).
f(t) = 5t + (-1); g(t) = 6t + (5). Find f(g(3)).
f(t) = 2t + (-4); g(t) = 2t + (3). Find f(g(-1)).
f(t) = 7t + (-5); g(t) = 2t + (-8). Find f(g(2)).
f(t) = 8t + (1); g(t) = 4t + (-8). Find f(g(-1)).
f(t) = 9t + (3); g(t) = 8t + (1). Find f(g(6)).
f(t) = 5t + (2); g(t) = 3t + (7). Find f(g(0)).
f(t) = 2t + (0); g(t) = 5t + (-2). Find f(g(5)).
f(t) = 9t + (-1); g(t) = 8t + (4). Find f(g(4)).
f(t) = 5t + (-9); g(t) = 4t + (-4). Find f(g(0)).
f(t) = 4t + (0); g(t) = 2t + (8). Find f(g(2)).
f(t) = 4t + (1); g(t) = 3t + (4). Find f(g(5)).
Answer key
- 234 g(8) = 32; f(32) = 234
- 114 g(3) = 23; f(23) = 114
- -2 g(-1) = 1; f(1) = -2
- -33 g(2) = -4; f(-4) = -33
- -95 g(-1) = -12; f(-12) = -95
- 444 g(6) = 49; f(49) = 444
- 37 g(0) = 7; f(7) = 37
- 46 g(5) = 23; f(23) = 46
- 323 g(4) = 36; f(36) = 323
- -29 g(0) = -4; f(-4) = -29
- 48 g(2) = 12; f(12) = 48
- 77 g(5) = 19; f(19) = 77
HS.F Functions
Quadratic functions
The axis of symmetry of a parabola.
Short lesson: Axis of symmetry
Study guide for Grades 10 to 12: 2 worked examples and 2 practice questions. The vertex lies on this vertical axis for y = ax² + bx + c.
x = −b/(2a), a ≠ 0
The vertex lies on this vertical axis for y = ax² + bx + c.
Worked example
The graph y = 1x² + 33x + 7 has axis x = k. Find k.
k = −33/(2 × 1) = -33/2
Answer: -33/2
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
The graph y = 10x² + 1x + 18 has axis x = k. Find k.
The graph y = 3x² + 38x + 1 has axis x = k. Find k.
The graph y = 6x² + 11x + 8 has axis x = k. Find k.
The graph y = 3x² + 37x + 11 has axis x = k. Find k.
The graph y = 9x² + 8x + 12 has axis x = k. Find k.
The graph y = 5x² + 17x + 18 has axis x = k. Find k.
The graph y = 6x² + 12x + 20 has axis x = k. Find k.
The graph y = 2x² + 3x + 15 has axis x = k. Find k.
The graph y = 9x² + 20x + 15 has axis x = k. Find k.
The graph y = 1x² + 12x + 13 has axis x = k. Find k.
The graph y = 8x² + 32x + 16 has axis x = k. Find k.
The graph y = 4x² + 18x + 20 has axis x = k. Find k.
Answer key
- -1/20 k = −1/(2 × 10) = -1/20
- -19/3 k = −38/(2 × 3) = -19/3
- -11/12 k = −11/(2 × 6) = -11/12
- -37/6 k = −37/(2 × 3) = -37/6
- -4/9 k = −8/(2 × 9) = -4/9
- -17/10 k = −17/(2 × 5) = -17/10
- -1 k = −12/(2 × 6) = -1
- -3/4 k = −3/(2 × 2) = -3/4
- -10/9 k = −20/(2 × 9) = -10/9
- -6 k = −12/(2 × 1) = -6
- -2 k = −32/(2 × 8) = -2
- -9/4 k = −18/(2 × 4) = -9/4
Review worksheet: 12 questions
The graph y = 8x² + 37x + 3 has axis x = k. Find k.
The graph y = 3x² + 37x + 15 has axis x = k. Find k.
The graph y = 7x² + 18x + 12 has axis x = k. Find k.
The graph y = 2x² + 31x + 11 has axis x = k. Find k.
The graph y = 5x² + 10x + 12 has axis x = k. Find k.
The graph y = 4x² + 15x + 19 has axis x = k. Find k.
The graph y = 1x² + 37x + 17 has axis x = k. Find k.
The graph y = 2x² + 1x + 1 has axis x = k. Find k.
The graph y = 2x² + 15x + 17 has axis x = k. Find k.
The graph y = 8x² + 40x + 3 has axis x = k. Find k.
The graph y = 2x² + 15x + 1 has axis x = k. Find k.
The graph y = 7x² + 3x + 4 has axis x = k. Find k.
Answer key
- -37/16 k = −37/(2 × 8) = -37/16
- -37/6 k = −37/(2 × 3) = -37/6
- -9/7 k = −18/(2 × 7) = -9/7
- -31/4 k = −31/(2 × 2) = -31/4
- -1 k = −10/(2 × 5) = -1
- -15/8 k = −15/(2 × 4) = -15/8
- -37/2 k = −37/(2 × 1) = -37/2
- -1/4 k = −1/(2 × 2) = -1/4
- -15/4 k = −15/(2 × 2) = -15/4
- -5/2 k = −40/(2 × 8) = -5/2
- -15/4 k = −15/(2 × 2) = -15/4
- -3/14 k = −3/(2 × 7) = -3/14
HS.F Functions
Sequences, logarithms and radians
Arithmetic sequences and geometric sequences.
Short lesson: Arithmetic sequences
Study guide for Grades 9 to 12: 2 worked examples and 2 practice questions. The first term is n = 1. Use one fewer step than the term number.
aₙ = a₁ + (n − 1)d
The first term is n = 1. Use one fewer step than the term number.
Worked example
An arithmetic sequence has first term 17 and common difference 2. Find term 24.
17 + (24 − 1) × 2 = 63
Answer: 63
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
An arithmetic sequence has first term 3 and common difference 11. Find term 19.
A geometric sequence starts at 11, with common ratio 2. Find term 4.
An arithmetic sequence has first term 31 and common difference 14. Find term 16.
A geometric sequence starts at 10, with common ratio 3. Find term 5.
An arithmetic sequence has first term 40 and common difference 12. Find term 5.
A geometric sequence starts at 10, with common ratio 2. Find term 3.
An arithmetic sequence has first term 2 and common difference 3. Find term 17.
A geometric sequence starts at 1, with common ratio 2. Find term 6.
An arithmetic sequence has first term 36 and common difference 14. Find term 14.
A geometric sequence starts at 5, with common ratio 4. Find term 6.
An arithmetic sequence has first term 39 and common difference 5. Find term 27.
A geometric sequence starts at 9, with common ratio 5. Find term 5.
Answer key
- 201 3 + (19 − 1) × 11 = 201
- 88 11 × 2^(4 − 1) = 88
- 241 31 + (16 − 1) × 14 = 241
- 810 10 × 3^(5 − 1) = 810
- 88 40 + (5 − 1) × 12 = 88
- 40 10 × 2^(3 − 1) = 40
- 50 2 + (17 − 1) × 3 = 50
- 32 1 × 2^(6 − 1) = 32
- 218 36 + (14 − 1) × 14 = 218
- 5120 5 × 4^(6 − 1) = 5120
- 169 39 + (27 − 1) × 5 = 169
- 5625 9 × 5^(5 − 1) = 5625
Review worksheet: 12 questions
An arithmetic sequence has first term 36 and common difference 9. Find term 17.
A geometric sequence starts at 11, with common ratio 2. Find term 6.
An arithmetic sequence has first term 15 and common difference 9. Find term 10.
A geometric sequence starts at 3, with common ratio 3. Find term 4.
An arithmetic sequence has first term 40 and common difference 4. Find term 25.
A geometric sequence starts at 4, with common ratio 2. Find term 4.
An arithmetic sequence has first term 20 and common difference 12. Find term 16.
A geometric sequence starts at 2, with common ratio 2. Find term 5.
An arithmetic sequence has first term 24 and common difference 2. Find term 18.
A geometric sequence starts at 5, with common ratio 3. Find term 6.
An arithmetic sequence has first term 34 and common difference 7. Find term 7.
A geometric sequence starts at 5, with common ratio 2. Find term 6.
Answer key
- 180 36 + (17 − 1) × 9 = 180
- 352 11 × 2^(6 − 1) = 352
- 96 15 + (10 − 1) × 9 = 96
- 81 3 × 3^(4 − 1) = 81
- 136 40 + (25 − 1) × 4 = 136
- 32 4 × 2^(4 − 1) = 32
- 200 20 + (16 − 1) × 12 = 200
- 32 2 × 2^(5 − 1) = 32
- 58 24 + (18 − 1) × 2 = 58
- 1215 5 × 3^(6 − 1) = 1215
- 76 34 + (7 − 1) × 7 = 76
- 160 5 × 2^(6 − 1) = 160
HS.G Geometry
Geometry
Volume of cones.
Short lesson: Volume of a cone
Study guide for Grades 8 to 12: 2 worked examples and 2 practice questions. Use the perpendicular height and radius, not the diameter.
V = πr²h/3
Use the perpendicular height and radius, not the diameter.
Worked example
A cone has radius 2 cm and height 90 cm. Use π = 3.14. Find its volume in cm³.
3.14 × 2² × 90 ÷ 3 = 376.8
Answer: 376.8 cm³
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
A cone has radius 8 cm and height 63 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 3 cm and height 30 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 7 cm and height 90 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 21 cm and height 30 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 14 cm and height 66 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 10 cm and height 51 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 11 cm and height 63 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 20 cm and height 63 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 18 cm and height 33 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 13 cm and height 57 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 10 cm and height 6 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 25 cm and height 75 cm. Use π = 3.14. Find its volume in cm³.
Answer key
- 4220.16 cm³ 3.14 × 8² × 63 ÷ 3 = 4220.16
- 282.6 cm³ 3.14 × 3² × 30 ÷ 3 = 282.6
- 4615.8 cm³ 3.14 × 7² × 90 ÷ 3 = 4615.8
- 13847.4 cm³ 3.14 × 21² × 30 ÷ 3 = 13847.4
- 13539.68 cm³ 3.14 × 14² × 66 ÷ 3 = 13539.68
- 5338 cm³ 3.14 × 10² × 51 ÷ 3 = 5338
- 7978.74 cm³ 3.14 × 11² × 63 ÷ 3 = 7978.74
- 26376 cm³ 3.14 × 20² × 63 ÷ 3 = 26376
- 11190.96 cm³ 3.14 × 18² × 33 ÷ 3 = 11190.96
- 10082.54 cm³ 3.14 × 13² × 57 ÷ 3 = 10082.54
- 628 cm³ 3.14 × 10² × 6 ÷ 3 = 628
- 49062.5 cm³ 3.14 × 25² × 75 ÷ 3 = 49062.5
Review worksheet: 12 questions
A cone has radius 12 cm and height 78 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 23 cm and height 90 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 13 cm and height 69 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 11 cm and height 21 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 7 cm and height 60 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 9 cm and height 6 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 22 cm and height 21 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 22 cm and height 78 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 15 cm and height 21 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 3 cm and height 63 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 14 cm and height 81 cm. Use π = 3.14. Find its volume in cm³.
A cone has radius 5 cm and height 90 cm. Use π = 3.14. Find its volume in cm³.
Answer key
- 11756.16 cm³ 3.14 × 12² × 78 ÷ 3 = 11756.16
- 49831.8 cm³ 3.14 × 23² × 90 ÷ 3 = 49831.8
- 12205.18 cm³ 3.14 × 13² × 69 ÷ 3 = 12205.18
- 2659.58 cm³ 3.14 × 11² × 21 ÷ 3 = 2659.58
- 3077.2 cm³ 3.14 × 7² × 60 ÷ 3 = 3077.2
- 508.68 cm³ 3.14 × 9² × 6 ÷ 3 = 508.68
- 10638.32 cm³ 3.14 × 22² × 21 ÷ 3 = 10638.32
- 39513.76 cm³ 3.14 × 22² × 78 ÷ 3 = 39513.76
- 4945.5 cm³ 3.14 × 15² × 21 ÷ 3 = 4945.5
- 593.46 cm³ 3.14 × 3² × 63 ÷ 3 = 593.46
- 16616.88 cm³ 3.14 × 14² × 81 ÷ 3 = 16616.88
- 2355 cm³ 3.14 × 5² × 90 ÷ 3 = 2355
HS.G Geometry
Right-triangle trigonometry
The tangent ratio and the sine ratio.
Short lesson: Sine in a right triangle
Study guide for Grades 9 to 12: 2 worked examples and 2 practice questions. Name the angle first; opposite is the side across from that angle.
sin θ = opposite / hypotenuse
Name the angle first; opposite is the side across from that angle.
Worked example
In a right triangle, the side opposite θ is 165 cm and the hypotenuse is 429 cm. Find sin θ as a fraction.
165/429 = 5/13
Answer: 5/13
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
In a right triangle, the legs opposite and adjacent to θ are 32 cm and 35 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 5 cm and the hypotenuse is 13 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 2 cm and 8 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 24 cm and the hypotenuse is 40 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 34 cm and 36 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 272 cm and the hypotenuse is 578 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 35 cm and 5 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 190 cm and the hypotenuse is 494 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 23 cm and 17 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 144 cm and the hypotenuse is 306 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 37 cm and 24 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 90 cm and the hypotenuse is 234 cm. Find sin θ as a fraction.
Answer key
- 32/35 32/35 = 32/35
- 5/13 5/13 = 5/13
- 1/4 2/8 = 1/4
- 3/5 24/40 = 3/5
- 17/18 34/36 = 17/18
- 8/17 272/578 = 8/17
- 7 35/5 = 7
- 5/13 190/494 = 5/13
- 23/17 23/17 = 23/17
- 8/17 144/306 = 8/17
- 37/24 37/24 = 37/24
- 5/13 90/234 = 5/13
Review worksheet: 12 questions
In a right triangle, the legs opposite and adjacent to θ are 3 cm and 24 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 80 cm and the hypotenuse is 208 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 7 cm and 32 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 95 cm and the hypotenuse is 247 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 38 cm and 9 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 140 cm and the hypotenuse is 364 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 36 cm and 38 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 75 cm and the hypotenuse is 125 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 31 cm and 20 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 3 cm and the hypotenuse is 5 cm. Find sin θ as a fraction.
In a right triangle, the legs opposite and adjacent to θ are 11 cm and 10 cm. Find tan θ as a fraction.
In a right triangle, the side opposite θ is 50 cm and the hypotenuse is 130 cm. Find sin θ as a fraction.
Answer key
- 1/8 3/24 = 1/8
- 5/13 80/208 = 5/13
- 7/32 7/32 = 7/32
- 5/13 95/247 = 5/13
- 38/9 38/9 = 38/9
- 5/13 140/364 = 5/13
- 18/19 36/38 = 18/19
- 3/5 75/125 = 3/5
- 31/20 31/20 = 31/20
- 3/5 3/5 = 3/5
- 11/10 11/10 = 11/10
- 5/13 50/130 = 5/13
HS.S Statistics and Probability
Statistics & probability
The mean of a frequency table, conditional probability from a table, variance, interquartile range, combinations and permutations.
Short lesson: Conditional probability from counts
Study guide for Grades 9 to 12: 2 worked examples and 2 practice questions. Restrict the denominator to the group named in the condition.
P(A | B) = count(A and B) / count(B)
Restrict the denominator to the group named in the condition.
Worked example
Club A has 6 bus users and 19 walkers. Club B has 16 bus users. Given that a student is in Club A, what is the probability they use the bus? Give a simplified fraction.
6/(6 + 19) = 6/25
Answer: 6/25
Worksheets
A practice worksheet and a review worksheet, 12 and 12 questions.
Practice worksheet: 12 questions
A score of 22 occurs 6 times; a score of 5 occurs 3 times. Find the mean as a fraction or decimal.
Data: 7, 15, 23, 31, 39, 47, 55, 63. Using medians of the lower four and upper four values, find the interquartile range.
How many ordered selections of 2 distinct items can be made from 12 items without repetition?
Find the population variance of 41, 42, 43, 44, 45. Divide by 5.
Club A has 9 bus users and 3 walkers. Club B has 3 bus users. Given that a student is in Club A, what is the probability they use the bus? Give a simplified fraction.
How many different groups of 4 can be chosen from 5 distinct people, if order does not matter?
A score of 19 occurs 10 times; a score of 8 occurs 4 times. Find the mean as a fraction or decimal.
Data: 20, 32, 44, 56, 68, 80, 92, 104. Using medians of the lower four and upper four values, find the interquartile range.
How many ordered selections of 5 distinct items can be made from 14 items without repetition?
Find the population variance of 25, 28, 31, 34, 37. Divide by 5.
Club A has 14 bus users and 4 walkers. Club B has 11 bus users. Given that a student is in Club A, what is the probability they use the bus? Give a simplified fraction.
How many different groups of 2 can be chosen from 14 distinct people, if order does not matter?
Answer key
- 49/3 (22 × 6 + 5 × 3)/(6 + 3) = 49/3
- 32 Q₁ = 19; Q₃ = 51; IQR = 32
- 132 12!/10! = 132
- 2 μ = 43; (4 + 1 + 0 + 1 + 4)/5 = 2
- 3/4 9/(9 + 3) = 3/4
- 5 5!/(4! × 1!) = 5
- 111/7 (19 × 10 + 8 × 4)/(10 + 4) = 111/7
- 48 Q₁ = 38; Q₃ = 86; IQR = 48
- 240240 14!/9! = 240240
- 18 μ = 31; (36 + 9 + 0 + 9 + 36)/5 = 18
- 7/9 14/(14 + 4) = 7/9
- 91 14!/(2! × 12!) = 91
Review worksheet: 12 questions
A score of 30 occurs 7 times; a score of 30 occurs 8 times. Find the mean as a fraction or decimal.
Data: 36, 42, 48, 54, 60, 66, 72, 78. Using medians of the lower four and upper four values, find the interquartile range.
Club A has 12 bus users and 7 walkers. Club B has 6 bus users. Given that a student is in Club A, what is the probability they use the bus? Give a simplified fraction.
Find the population variance of 10, 16, 22, 28, 34. Divide by 5.
How many different groups of 5 can be chosen from 14 distinct people, if order does not matter?
How many ordered selections of 5 distinct items can be made from 10 items without repetition?
A score of 18 occurs 2 times; a score of 28 occurs 2 times. Find the mean as a fraction or decimal.
Data: 38, 45, 52, 59, 66, 73, 80, 87. Using medians of the lower four and upper four values, find the interquartile range.
Club A has 13 bus users and 10 walkers. Club B has 13 bus users. Given that a student is in Club A, what is the probability they use the bus? Give a simplified fraction.
Find the population variance of 10, 17, 24, 31, 38. Divide by 5.
How many different groups of 5 can be chosen from 9 distinct people, if order does not matter?
How many ordered selections of 4 distinct items can be made from 11 items without repetition?
Answer key
- 30 (30 × 7 + 30 × 8)/(7 + 8) = 30
- 24 Q₁ = 45; Q₃ = 69; IQR = 24
- 12/19 12/(12 + 7) = 12/19
- 72 μ = 22; (144 + 36 + 0 + 36 + 144)/5 = 72
- 2002 14!/(5! × 9!) = 2002
- 30240 10!/5! = 30240
- 23 (18 × 2 + 28 × 2)/(2 + 2) = 23
- 28 Q₁ = 48.5; Q₃ = 76.5; IQR = 28
- 13/23 13/(13 + 10) = 13/23
- 98 μ = 24; (196 + 49 + 0 + 49 + 196)/5 = 98
- 126 9!/(5! × 4!) = 126
- 7920 11!/7! = 7920