An ideal capacitor of 261 μF is at 80 V. Calculate its stored energy in millijoules. Round the final result to 4 decimal places if needed. Answer in mJ.
Answer and explanation
835.2 mJ
U = (261 × 10⁻⁶)(80)²/2 J. Multiply joules by 1000 for mJ.
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835.2 mJ
U = (261 × 10⁻⁶)(80)²/2 J. Multiply joules by 1000 for mJ.
19.1633 V
RC = (18×1000)(130×10⁻⁶) = 2.34 s; substitute into V₀ exp(−t/RC).
3162.4125 N·m²/C
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