Physics · Advanced university
Vacuum electric-field energy density · formula reference
This asks for the electric contribution only. A magnetic field would add B²/(2μ₀).
Formula
This asks for the electric contribution only. A magnetic field would add B²/(2μ₀).
uE = ε₀E²/2
Worked example
In vacuum E=24 kV/m. Use ε₀=8.854×10⁻¹² F/m. Find electric-field energy density in μJ/m³. Round the final result to 4 decimal places if needed. Answer in μJ/m³.
Convert E to 24×10³ V/m. Compute ε₀E²/2 in J/m³, then multiply by 10⁶.
2549.952 μJ/m³
Prerequisites and checking
Algebra, calculus and the stated physical model. Keep units and rounding consistent. State the model conditions before applying the formula.
Further reading and review references
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