Physics · University
Gauss-law electric flux
Net flux through the entire closed surface depends on enclosed charge, not on external charges.
Method and conditions
Net flux through the entire closed surface depends on enclosed charge, not on external charges.
ΦE = Qenclosed/ε₀
Worked examples
A closed surface encloses -70 nC. Using ε₀=8.854×10⁻¹² F/m, find the net electric flux in N·m²/C. Round the final result to 4 decimal places if needed. Answer in N·m²/C.
Convert charge to -70×10⁻⁹ C and divide by ε₀. The sign follows the enclosed charge.
-7906.0312 N·m²/C
A closed surface encloses 5 nC. Using ε₀=8.854×10⁻¹² F/m, find the net electric flux in N·m²/C. Round the final result to 4 decimal places if needed. Answer in N·m²/C.
Convert charge to 5×10⁻⁹ C and divide by ε₀. The sign follows the enclosed charge.
564.7165 N·m²/C
Try it
A closed surface encloses -56 nC. Using ε₀=8.854×10⁻¹² F/m, find the net electric flux in N·m²/C. Round the final result to 4 decimal places if needed. Answer in N·m²/C.
A closed surface encloses -70 nC. Using ε₀=8.854×10⁻¹² F/m, find the net electric flux in N·m²/C. Round the final result to 4 decimal places if needed. Answer in N·m²/C.
Check your work
Answers and marking notes
- -6324.8249 N·m²/C
Convert charge to -56×10⁻⁹ C and divide by ε₀. The sign follows the enclosed charge.
- -7906.0312 N·m²/C
Convert charge to -70×10⁻⁹ C and divide by ε₀. The sign follows the enclosed charge.
Further reading and review references
These are reference links, not copied exercises, institutional endorsement or proof of independent review.
AI-assisted preview; independent educational review required. Level labels describe prerequisites, not accreditation or official curriculum alignment.