A fixed-axis rotor has I=3 kg m² and net torque 12 N m. Find its angular acceleration.
Answer and explanation
4 rad/s²
Use angular acceleration = torque/I = 12/3.
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4 rad/s²
Use angular acceleration = torque/I = 12/3.
25 J
K=Iω²/2=(2)(25)/2.
5 rad/s
The rolling constraint gives ω=v/R=2/0.4.
Moving some mass farther from that axis
Inertia is the mass-weighted squared distance from the specified axis.
The cylinder has translational energy mv²/2 plus rotation about its centre Iω²/2. The point-mass model includes only translation.
Credit both terms and use of the same centre speed; do not claim that all rolling bodies have the same I.
27 J
Translation is 18 J and rotation is mv²/4=9 J.
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