Physics · University
Driven oscillations, damping and resonance
A linear mass-spring oscillator obeys mx″+kx=0. Its natural angular frequency is sqrt(k/m), not k/m.
Prerequisites
Second-order differential equations and complex numbers.
Study notes
Free motion
A linear mass-spring oscillator obeys mx″+kx=0. Its natural angular frequency is sqrt(k/m), not k/m.
Damping
A viscous damping force −bx′ converts the equation to mx″+bx′+kx=0. In underdamping, the oscillation envelope decays exponentially.
Driving
A periodic external force can transfer energy to the oscillator. The steady response depends on drive frequency, damping and phase.
Resonance
A finite drive does not imply infinite amplitude in a damped physical oscillator. Transient motion and nonlinear limits matter.
Worked examples
For m=2 kg and k=18 N/m, find the undamped angular frequency.
ω0=sqrt(k/m)=sqrt(9).
3 rad/s
Which force represents linear viscous damping?
The force opposes velocity and removes mechanical energy.
−b times velocity with b positive
Check your understanding
An underdamped amplitude follows A(t)=8 exp(−t/2) cm. Find the exponential decay time constant.
What distinguishes a transient from a steady driven response?
- A transient must last forever
- A steady response has no frequency
- A transient depends on initial conditions and may decay
- A steady response cannot lose energy
Why does energy not grow without limit in an ordinary damped oscillator driven near resonance?
If k is multiplied by 4 at fixed mass, by what factor does ω0 change?
Answers and marking guidance
Answers and marking notes
- 2 s
Write the envelope as A0 exp(−t/τ); τ=2 s.
- A transient depends on initial conditions and may decay
Damping can remove the initial-condition contribution while driving maintains a steady oscillation.
- In steady state, average driving power balances dissipated power. Damping limits the linear response, and large-amplitude nonlinearities can further change it.
Credit energy balance and avoidance of an undamped infinite-amplitude generalization.
- 2
ω0 scales as sqrt(k).
Further reading and review references
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