Find the coefficient of x³ in the Maclaurin series of exp(2x).
Answer and explanation
4/3
The coefficient is 2³/3!=8/6=4/3.
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4/3
The coefficient is 2³/3!=8/6=4/3.
4
This geometric series converges for abs(x/4)<1.
It diverges
At x=1 this is the harmonic series. The radius alone does not settle endpoints.
It converges conditionally
The alternating harmonic series converges but its absolute-value series diverges.
1.105
Substitution gives 1+0.1+0.005=1.105; this is an approximation to exp(0.1).
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