For Vmax=10, Km=2 and substrate concentration 2 in consistent units, find rate.
Answer and explanation
5
v=10×2/(2+2)=5.
Subjects
Choose questions individually, practise online, or create a worksheet with matching answers. Counts include generated variants, not only authored originals.
5
v=10×2/(2+2)=5.
1/2
Substitute [S]=Km into the model.
No
Catalysis changes rates, not the thermodynamic equilibrium constant.
9
12×9/(3+9)=9.
In the model, the rate approaches Vmax as substrate greatly exceeds Km, reflecting saturation behaviour.
Credit asymptotic saturation under the model.
Its interpretation depends on the kinetic mechanism
Mechanistic assumptions determine how Km relates to other constants.
Enzymes catalyse reactions without being consumed in the net reaction. They alter rates but not the equilibrium constant for a given reaction and conditions.
UniversityEnzymes catalyse reactions without being consumed in the net reaction. They alter rates but not the equilibrium constant for a given reaction and conditions.
UniversityAssume the stated steady-state model applies; Vmax and v share units, and Km and substrate concentration share units.
UniversityAssume the stated steady-state model applies; Vmax and v share units, and Km and substrate concentration share units.
University