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Electrochemistry

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University · Electrochemistry

At 298 K use E=E°−(0.05916/n)log₁₀Q. Given E°=1.4 V, n=1, and Q=10^(-2), find E. Round the final result to 4 decimal places if needed. Answer in V.

Answer and explanation

1.5183 V

log₁₀Q=-2. Therefore E=1.4−(0.05916/1)(-2).

University · Electrochemistry

At 298 K use E=E°−(0.05916/n)log₁₀Q. Given E°=3 V, n=4, and Q=10^(4), find E. Round the final result to 4 decimal places if needed. Answer in V.

Answer and explanation

2.9408 V

log₁₀Q=4. Therefore E=3−(0.05916/4)(4).

University · Electrochemistry

At 298 K use E=E°−(0.05916/n)log₁₀Q. Given E°=1.4 V, n=6, and Q=10^(-3), find E. Round the final result to 4 decimal places if needed. Answer in V.

Answer and explanation

1.4296 V

log₁₀Q=-3. Therefore E=1.4−(0.05916/6)(-3).

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