Mathematics · University
Integration by parts with a logarithm
Here n > −1. Treat x = 0 as an improper endpoint and use its limiting boundary term.
Method and conditions
Here n > −1. Treat x = 0 as an improper endpoint and use its limiting boundary term.
∫₀¹ xⁿ ln(x) dx = −1/(n + 1)²
Worked examples
Evaluate the improper integral from 0 to 1 of 9 x^1 ln(x) dx. Round the final result to 4 decimal places if needed.
Use u = ln x and dv = 9x^1 dx. The boundary term vanishes; the remaining integral is −9/(2)².
-2.25
Evaluate the improper integral from 0 to 1 of 8 x^12 ln(x) dx. Round the final result to 4 decimal places if needed.
Use u = ln x and dv = 8x^12 dx. The boundary term vanishes; the remaining integral is −8/(13)².
-0.0473
Try it
Evaluate the improper integral from 0 to 1 of 13 x^16 ln(x) dx. Round the final result to 4 decimal places if needed.
Evaluate the improper integral from 0 to 1 of 9 x^6 ln(x) dx. Round the final result to 4 decimal places if needed.
Check your work
Answers and marking notes
- -0.045
Use u = ln x and dv = 13x^16 dx. The boundary term vanishes; the remaining integral is −13/(17)².
- -0.1837
Use u = ln x and dv = 9x^6 dx. The boundary term vanishes; the remaining integral is −9/(7)².
Further reading and review references
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