Physics · Advanced university
Scattering, currents and probability conservation
Scattering models compare incoming and outgoing waves far from a localized interaction. Boundary conditions identify which waves are physically incident.
Prerequisites
Wave mechanics, complex amplitudes and boundary matching.
Study notes
Asymptotic waves
Scattering models compare incoming and outgoing waves far from a localized interaction. Boundary conditions identify which waves are physically incident.
Current
For a nonrelativistic one-dimensional wave, j=(ℏ/m) Im(ψ* ∂ψ/∂x). For a plane wave, current includes wave number as well as amplitude.
Transmission
Transmission probability is a transmitted-to-incident flux ratio. It is not always the squared transmission-amplitude ratio when wave numbers differ.
Conservation
For a real, time-independent nonabsorbing potential with the usual scattering channels, R+T=1. Absorption or additional channels require fuller accounting.
Worked examples
What determines transmission probability in one-dimensional scattering?
Current accounts for both amplitude and propagation factors.
The transmitted-to-incident probability-current ratio
In a nonabsorbing two-channel problem, R=0.3. Find T.
Conservation gives R+T=1.
0.7
Check your understanding
If transmitted and incident wave numbers are equal and amplitude ratio is 0.5, find T.
When unequal wave numbers occur, what must a transmission calculation include?
- Only the incident phase
- A factor of zero
- Only squared amplitude with no correction
- Their appropriate current ratio
Use kt/ki=2 and squared transmission-amplitude ratio 0.2. Find T.
Why can a wavefunction be nonzero in a classically forbidden finite barrier?
Answers and marking guidance
Answers and marking notes
- 0.25
With equal flux factors, T is squared amplitude magnitude.
- Their appropriate current ratio
For equal masses, the plane-wave current ratio includes kt/ki.
- 0.4
Multiply the flux factor by squared amplitude ratio.
- The Schrodinger equation admits an evanescent solution in the barrier. Matching through a finite region can produce transmitted flux beyond it.
Credit finite-barrier matching, not a classical trajectory with negative kinetic energy.
Further reading and review references
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