Mathematics · Advanced university
Holomorphic functions and Cauchy-Riemann equations
A derivative must have the same limit along every complex direction.
Prerequisites
Complex arithmetic and partial derivatives.
Study notes
Complex differentiability
A derivative must have the same limit along every complex direction.
Cauchy-Riemann
For f=u+iv, differentiability implies u_x=v_y and u_y=−v_x when the partials exist.
Sufficient hypotheses
Continuous partial derivatives satisfying the equations on a neighborhood give holomorphicity there.
Not a point test
Equations at one isolated point alone do not prove holomorphicity throughout a neighborhood.
Worked examples
Verify the Cauchy-Riemann equations for f(z)=z².
Credit both equations and smoothness of the partials.
u=x²−y² and v=2xy. Then u_x=2x=v_y and u_y=−2y=−v_x.
For f(z)=z³, find the real derivative value f′(2).
f′(z)=3z², so f′(2)=12.
12
Check your understanding
Is complex conjugation f(z)=conjugate(z) holomorphic on an open subset of C?
- It is a polynomial in z
- No
- Only because it is continuous
- Yes everywhere
Use directional difference quotients to show conjugation is not complex differentiable at zero.
What does a power series define inside its radius of convergence?
- A function with no derivative
- A necessarily constant function
- Only a function on the real axis
- A holomorphic function
For f(z)=z² at z=i, write f′(i)=a i and find a.
Answers and marking guidance
Answers and marking notes
- No
For u=x,v=−y, u_x=1 but v_y=−1, so the Cauchy-Riemann equations fail.
- Along real h, conjugate(h)/h=1; along imaginary h, the quotient is −1. The limits disagree.
Credit two directions with distinct limiting quotients.
- A holomorphic function
Complex power series can be differentiated termwise inside their convergence disk.
- 2
f′(z)=2z, hence 2i.
Further reading and review references
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