Physics · Grades 10–12
Horizontal projectile range
Initial vertical velocity is zero; ignore air resistance and use level ground below.
Rule and assumptions
Initial vertical velocity is zero; ignore air resistance and use level ground below.
t = √(2h/g); x = vₓt
Worked examples
A model object leaves a ledge horizontally at 21 m/s from height 245 m. Use g = 10 m/s² and no air resistance. Find its horizontal range to the ground. Round to 3 decimal places if needed. Answer in m.
t = √(2h/g); x = vₓt √(2 × 245 / 10) = 7; 21 × 7 = 147
147 m
A model object leaves a ledge horizontally at 9 m/s from height 180 m. Use g = 10 m/s² and no air resistance. Find its horizontal range to the ground. Round to 3 decimal places if needed. Answer in m.
t = √(2h/g); x = vₓt √(2 × 180 / 10) = 6; 9 × 6 = 54
54 m
Try two questions
A model object leaves a ledge horizontally at 35 m/s from height 320 m. Use g = 10 m/s² and no air resistance. Find its horizontal range to the ground. Round to 3 decimal places if needed. Answer in m.
A model object leaves a ledge horizontally at 25 m/s from height 245 m. Use g = 10 m/s² and no air resistance. Find its horizontal range to the ground. Round to 3 decimal places if needed. Answer in m.
Answers and reasoning
Answers and marking notes
- 280 m
t = √(2h/g); x = vₓt √(2 × 320 / 10) = 8; 35 × 8 = 280
- 175 m
t = √(2h/g); x = vₓt √(2 × 245 / 10) = 7; 25 × 7 = 175
Further reading and review references
These are reference links, not copied exercises, institutional endorsement or proof of independent review.
Learning preview · independent educational and translation review required. Suggested grades are not official curriculum alignment.