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Physics · Grades 9–12

Liquid pressure increase

This is pressure above the surface pressure, not absolute pressure.

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Rule and assumptions

This is pressure above the surface pressure, not absolute pressure.

Δp = ρgh

Worked examples

A liquid has uniform density 1200 kg/m³. At depth 23 m, with g = 10 m/s², find pressure above its surface pressure. Round to 3 decimal places if needed. Answer in Pa.

Δp = ρgh 1200 × 10 × 23 = 276000

276000 Pa

A liquid has uniform density 1000 kg/m³. At depth 16 m, with g = 10 m/s², find pressure above its surface pressure. Round to 3 decimal places if needed. Answer in Pa.

Δp = ρgh 1000 × 10 × 16 = 160000

160000 Pa

Try two questions

  1. A liquid has uniform density 1000 kg/m³. At depth 9 m, with g = 10 m/s², find pressure above its surface pressure. Round to 3 decimal places if needed. Answer in Pa.

  2. A liquid has uniform density 1200 kg/m³. At depth 19 m, with g = 10 m/s², find pressure above its surface pressure. Round to 3 decimal places if needed. Answer in Pa.

Answers and reasoning

Answers and marking notes
  1. 90000 Pa

    Δp = ρgh 1000 × 10 × 9 = 90000

  2. 228000 Pa

    Δp = ρgh 1200 × 10 × 19 = 228000

Further reading and review references

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Learning preview · independent educational and translation review required. Suggested grades are not official curriculum alignment.