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Physics · Grades 10–12

Energy for a phase change

At the phase-change temperature, use latent heat rather than a temperature-rise formula.

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Rule and assumptions

At the phase-change temperature, use latent heat rather than a temperature-rise formula.

Q = mL

Worked examples

A 400 g sample completely melts at its melting temperature. Its latent heat is 360000 J/kg. Ignore losses. Find energy required. Round to 3 decimal places if needed. Answer in J.

Q = mL (400/1000) × 360000 = 144000

144000 J

A 590 g sample completely melts at its melting temperature. Its latent heat is 200000 J/kg. Ignore losses. Find energy required. Round to 3 decimal places if needed. Answer in J.

Q = mL (590/1000) × 200000 = 118000

118000 J

Try two questions

  1. A 690 g sample completely melts at its melting temperature. Its latent heat is 280000 J/kg. Ignore losses. Find energy required. Round to 3 decimal places if needed. Answer in J.

  2. A 90 g sample completely melts at its melting temperature. Its latent heat is 260000 J/kg. Ignore losses. Find energy required. Round to 3 decimal places if needed. Answer in J.

Answers and reasoning

Answers and marking notes
  1. 193200 J

    Q = mL (690/1000) × 280000 = 193200

  2. 23400 J

    Q = mL (90/1000) × 260000 = 23400

Further reading and review references

These are reference links, not copied exercises, institutional endorsement or proof of independent review.

Learning preview · independent educational and translation review required. Suggested grades are not official curriculum alignment.