Physics · Grades 9–12
Energy for a temperature rise
Assume constant specific heat, no phase change and no energy loss.
Rule and assumptions
Assume constant specific heat, no phase change and no energy loss.
Q = mcΔT
Worked examples
A 2.5 kg sample with specific heat 2100 J/(kg·°C) warms by 48 °C. No phase change or heat loss occurs. Find energy supplied. Round to 3 decimal places if needed. Answer in J.
Q = mcΔT 2.5 × 2100 × 48 = 252000
252000 J
A 1.9 kg sample with specific heat 2100 J/(kg·°C) warms by 42 °C. No phase change or heat loss occurs. Find energy supplied. Round to 3 decimal places if needed. Answer in J.
Q = mcΔT 1.9 × 2100 × 42 = 167580
167580 J
Try two questions
A 0.6 kg sample with specific heat 900 J/(kg·°C) warms by 39 °C. No phase change or heat loss occurs. Find energy supplied. Round to 3 decimal places if needed. Answer in J.
A 2.2 kg sample with specific heat 2100 J/(kg·°C) warms by 17 °C. No phase change or heat loss occurs. Find energy supplied. Round to 3 decimal places if needed. Answer in J.
Answers and reasoning
Answers and marking notes
- 21060 J
Q = mcΔT 0.6 × 900 × 39 = 21060
- 78540 J
Q = mcΔT 2.2 × 2100 × 17 = 78540
Further reading and review references
These are reference links, not copied exercises, institutional endorsement or proof of independent review.
Learning preview · independent educational and translation review required. Suggested grades are not official curriculum alignment.