Mathematics · Grades 8–11
Find the mistake: algebra
Apply the same valid operation to both sides and respect restrictions such as division by zero.
Understand the idea
Keep equations balanced
Apply the same valid operation to both sides and respect restrictions such as division by zero.
Check by substitution
Substituting a proposed solution into the original equation can expose an error.
Examples and reasoning
A pupil expands 3(x + 4) as 3x + 4. Correct it.
3x + 12. The factor 3 multiplies both terms.
3x + 12. The factor 3 multiplies both terms.
A pupil says (x + 5)² = x² + 25. What is missing?
The middle term 10x is missing: (x + 5)² = x² + 10x + 25.
The middle term 10x is missing: (x + 5)² = x² + 10x + 25.
Check your understanding
A pupil combines 2x + 3x² as 5x³. Explain the error.
Solve 4x − 7 = 21.
Solve 5x + 2 = 3x + 18.
Solving −2x > 6 gives
- x < 3
- x < −3
- x > −3
- x > 3
Answers and marking notes
Answers and marking notes
- x and x² are unlike terms and cannot be added by adding exponents; the expression remains 3x² + 2x.
x and x² are unlike terms and cannot be added by adding exponents; the expression remains 3x² + 2x.
- 7
4x = 28, so x = 7.
- 8
2x = 16, so x = 8.
- x < −3
x < −3
Further reading and review references
These are reference links, not copied exercises, institutional endorsement or proof of independent review.
Learning preview · teacher review required. Grade bands are approximate, not official curriculum alignment.