Science · Grades 8–12
Ohm’s law
Applies to an ohmic component under constant physical conditions.
The key idea
Applies to an ohmic component under constant physical conditions.
V = IR
Worked examples
An ideal ohmic resistor of 42 Ω carries 6 A. Find the voltage across it in V.
6 × 42 = 252
252 V
An ideal ohmic resistor of 65 Ω carries 9 A. Find the voltage across it in V.
9 × 65 = 585
585 V
Try it yourself
An ideal ohmic resistor of 20 Ω carries 6 A. Find the voltage across it in V.
An ideal ohmic resistor of 53 Ω carries 1 A. Find the voltage across it in V.
Check your understanding
Answers and marking notes
- 120 V
6 × 20 = 120
- 53 V
1 × 53 = 53
Further reading and review references
These are reference links, not copied exercises, institutional endorsement or proof of independent review.
Learning preview · teacher review required. Grade bands are approximate, not official curriculum alignment.