Mathematics · Grades 10–12
Combinations
Use combinations when order does not matter and items are chosen without replacement.
The key idea
Use combinations when order does not matter and items are chosen without replacement.
C(n,r) = n!/[r!(n − r)!]
Worked examples
How many different groups of 3 can be chosen from 10 distinct people, if order does not matter?
10!/(3! × 7!) = 120
120
How many different groups of 3 can be chosen from 11 distinct people, if order does not matter?
11!/(3! × 8!) = 165
165
Try it yourself
How many different groups of 3 can be chosen from 11 distinct people, if order does not matter?
How many different groups of 2 can be chosen from 5 distinct people, if order does not matter?
Check your understanding
Answers and marking notes
- 165
11!/(3! × 8!) = 165
- 10
5!/(2! × 3!) = 10
Further reading and review references
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Learning preview · teacher review required. Grade bands are approximate, not official curriculum alignment.